Icahn Charter School 3

Icahn Charter School 3 - Review the parameters passed to the createwindowex function. This is what argument of type 'char*' is incompatible with parameter of type 'char**' means. This function counts lenght of a string entered at the command line argument. Your function first parameter is of type but you are calling the function with an argument of type. When is an argument of type incompatible with a parameter? “argument of type ‘const char*’ is incompatible with parameter of type ‘char*'”. Because the arguments are wrong, it's treating the format string as the file pointer, and the second argument as the format string. You can do this by passing in the address. Change the signature of your function accordingly and it will work. The first argument to fprintf should be the file pointer.

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Im Writing A Funtion That Takes String As A Argument And Gives Back A Integer.

This is what argument of type 'char*' is incompatible with parameter of type 'char**' means. Because the arguments are wrong, it's treating the format string as the file pointer, and the second argument as the format string. Check if the type of the function has a constructor that can be called with the given types. You have to use a local string:

You Can Do This By Passing In The Address.

You should fix your function prototype (and body) to work with a parameter. This function counts lenght of a string entered at the command line argument. The first argument to fprintf should be the file pointer. I get an error :.

When Is An Argument Of Type Incompatible With A Parameter?

“argument of type ‘const char*’ is incompatible with parameter of type ‘char*'”. Change the signature of your function accordingly and it will work. If it doesn’t have such a constructor, replace it by a valid default argument. To fix this, simply pass in a char **;

Your Functions Expects A Char* As An Argument, But You Are Passing It A Const Char* (Because Its A Literal).

Review the parameters passed to the createwindowex function. Your function first parameter is of type but you are calling the function with an argument of type.

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